Example 10 - Factorise x3 - 23x2 + 142x - 120 - Class 9 - Factorizing
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Example 15: Factorise x3−23x2+142x−120.Solution : Let p(x)=x3−23x2+142x−..
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Example 15 : Factorise x3−23x2+142x−120.olution : Let p(x)=x3−23x2+142x−..
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x3−23x2−142x−120 =(x−12)(x−10)=(x−1)(x−10)(x−12) EXERCISE 2.4Determine
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x3−23x2−142x−120 =x(x−12)−10(x−12)=(x−12)(x−10)=(x−1)(x−10)(x−12) EXERCI..
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x3−23x2−142x−120 =x(x−12)−10(x−12)=(x−12)(x−10)=(x−1)(x−10)(x−12) EXERC..
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x3−23x2−142x−120=(x−1)(x−10)(x−12)EXERCISE 2.3Determine which of the f..
=(x−12)(x−10)So,x3−23x2−142x−120=(x−1)(x−10)(x−12)EXERCISE 2.41. Dete..
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x2−22x+120x3−23x2−142x−120 =x2−12x−10x+120=x(x−12)−10(x−12)=(x−12)(x−10)=..
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1. Factorise.(1) x2+9x+18(4) 5y2+5y−10(7) m2−23m+120(10) 2x2+x−45..
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So, =(x−12)(x−10)x3−23x2−142x−120=(x−1)(x−10)(x−12)EXEIRCISE 2.41. Det..
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